Hello I am designing a procedure for some maximization that I want to do. The solution, are choices that agents do, and I want to store the numerical values (feasible) and the names of those choices (I don't know how to do it). Ideally, I was thinking to code something like the following:
struct res_wage {
array res_wage ;
string array names;
};
struct res_wage VF_no_work2;
VF_no_work2.res_wage = arrayinit(N_s|N_s|2|2|N_w|10,miss(1, 1)) ;
VF_no_work2.names =arrayinit(N_s|N_s|2|2|1|10,"hg") ;
But, the later shows an error, is there any way I can store the strings on different dimensions inside a structure definition?
Thank you
3 Answers
0
It might be simpler to make a multidimensional structure. I don't know the best way to lay out your data, but you can create vectors or arrays of structures.
new;
struct choices {
matrix wage;
string array name;
};
struct choices market_a;
// Initialize (if desired. you don't have to)
market_a.wage = { 1 2, 3 4 };
market_a.name = { "alpha" "beta", "gamma" "delta" };
// Reshape to a 9x2 matrix of 'choices' structures
market_a = reshape(market_a, 9, 2);
// Print the elements of the structure in row 3, column 2
print market_a[3,2].name;
print market_a[3,2].wage;
0
Thanks for your answer, I have a lot of dimensions that I am considering, can I do the areshape, instead of the reshape ( I tried and it didn't work)?
0
Structures can only be reshaped with two dimensions. However, you can make your structure the member of another structure if you need to get more dimensions.
new;
struct choices {
matrix wage;
string array name;
};
struct choice_main {
struct choices c;
};
struct choice_main markets_all;
// Initialize (if desired. you don't have to)
markets_all.c.wage = { 1 2, 3 4 };
markets_all.c.name = { "alpha" "beta", "gamma" "delta" };
// Reshape substruct to a 9x2 matrix of 'choices' structures
markets_all.c = reshape(markets_all.c, 9, 2);
// Reshape main struct to a 4x3 matrix of 'choice_main' structures
markets_all = reshape(markets_all, 4, 3);
// Print the elements of the structure in row 3, column 2
print markets_all[2,1].c[3,2].name;
print markets_all[2,1].c[3,2].wage;For this, I would create procedures to do the initialization of these structures to keep the complexity out of your main code. Good names will also help quite a bit.
Your Answer
3 Answers
It might be simpler to make a multidimensional structure. I don't know the best way to lay out your data, but you can create vectors or arrays of structures.
new;
struct choices {
matrix wage;
string array name;
};
struct choices market_a;
// Initialize (if desired. you don't have to)
market_a.wage = { 1 2, 3 4 };
market_a.name = { "alpha" "beta", "gamma" "delta" };
// Reshape to a 9x2 matrix of 'choices' structures
market_a = reshape(market_a, 9, 2);
// Print the elements of the structure in row 3, column 2
print market_a[3,2].name;
print market_a[3,2].wage;Thanks for your answer, I have a lot of dimensions that I am considering, can I do the areshape, instead of the reshape ( I tried and it didn't work)?
Structures can only be reshaped with two dimensions. However, you can make your structure the member of another structure if you need to get more dimensions.
new;
struct choices {
matrix wage;
string array name;
};
struct choice_main {
struct choices c;
};
struct choice_main markets_all;
// Initialize (if desired. you don't have to)
markets_all.c.wage = { 1 2, 3 4 };
markets_all.c.name = { "alpha" "beta", "gamma" "delta" };
// Reshape substruct to a 9x2 matrix of 'choices' structures
markets_all.c = reshape(markets_all.c, 9, 2);
// Reshape main struct to a 4x3 matrix of 'choice_main' structures
markets_all = reshape(markets_all, 4, 3);
// Print the elements of the structure in row 3, column 2
print markets_all[2,1].c[3,2].name;
print markets_all[2,1].c[3,2].wage;For this, I would create procedures to do the initialization of these structures to keep the complexity out of your main code. Good names will also help quite a bit.